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Calculus: Differential Equations


Contents (2 topics • 18 videos)



 Separable Differential Equations
Introduction Videos
Separable Differential Equations with General Solutions  
Separable Differential Equations with Particular Solutions  


Theorems and Definitions
Separable Differential Equations The first-order differential equation of the form \[ \frac{dy}{dx} = H(x, y) \] is called separable if the variables \(x\) and \(y\) can be separated and the equation can be written in the form \[ f(y) \text{ } dy = g(x) \text{ } dx \]



Video Practice Problems Playlist on YouTube  
Find the general solution.
\[ \frac{dy}{dx}=\frac{12x^3}{4y-\sin{y}} \]
Find the general solution.
\[ \frac{dy}{dx}=3x \sqrt{y} \]
Find the general solution.
\[ x y'=3(y-2) \]
Find the general solution.
\[ \frac{dy}{dx}=e^{x-2y} \]
Use the initial condition to find the particular solution.
\[ y \cdot y'-5e^x=10 \quad \quad y(0)=2 \]
Use the initial condition to find the particular solution.
\[ 2y \cdot y'=4 \sin{x} \quad \quad y \Big( \frac{\pi}{4} \Big) =\sqrt{2} \]
Use the initial condition to find the particular solution.
\[ \sqrt{x} -\sqrt{y} \cdot y' = 0 \quad \quad y(9)=1 \]
Use the initial condition to find the particular solution.
\[ y(2x-1)+y'=0 \quad \quad y(-3)=e \]
Use the initial condition to find the particular solution.
\[ y \cdot \ln{x} - xy'=0 \quad \quad y \big(e^2 \big)=1 \]
Use the initial condition to find the particular solution.
\[ y' = x y \sin{x^2} \quad \quad y(0)=\sqrt{e} \]



Documents
Practice Problems (.PDF)  
Practice Problems - Solutions (.PDF)  






 First-Order Linear Differential Equations
Introduction Videos
First-Order Linear Differential Equations  


Theorems and Definitions
First-Order Linear Differential Equations A first-order linear differential equation is an equation of the form \[ \frac{dy}{dx} + P(x) \cdot y=Q(x) \] where \(P\) and \(Q\) are continuous functions of \(x\). This first-order linear differential equation is said to be in standard form.

An integrating factor for the first-order linear differential equation is \[ r(x) = e^{ \int{ P(x) \text{ } dx }}. \] The solution of the differential equation is \[ y \cdot r(x) = \int{ Q(x) \cdot r(x) \text{ } dx }. \]



Video Practice Problems Playlist on YouTube  
Find the general solution.
\[ y'+y=3 \]
Find the general solution.
\[ y'+y=e^{-x} \]
Find the general solution.
\[ 2xy'+y=10\sqrt{x} \]
Use the initial condition to find the particular solution.
\[ xy'-4y=6x^{3} \quad \quad y(2)=24 \]
Use the initial condition to find the particular solution.
\[ xy'+3y=\frac{\ln x}{x^{2}} \quad \quad y(1)=3 \]



Documents
Practice Problems (.PDF)  
Practice Problems - Solutions (.PDF)  




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